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让tomcat支持shtml文件

时间:2010-6-25来源:互联网 点击:
    服务器上要需要运行shtml,必须在web服务器上配置好ssi。下面是ssi在tomcat5.*上的配置方法:

打开tomcat配置文件:conf/web.xml:
1、去掉下面servlet前的注释

/* <servlet>
<servlet-name>ssi</servlet-name>
<servlet-class>
org.apache.catalina.ssi.SSIServlet
</servlet-class>
<init-param>
<param-name>buffered</param-name>
<param-value>1</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>expires</param-name>
<param-value>666</param-value>
</init-param>
<init-param>
<param-name>isVirtualWebappRelative</param-name>
<param-value>0</param-value>
</init-param>
<load-on-startup>4</load-on-startup>
</servlet>
*/

改成

<servlet>
<servlet-name>ssi</servlet-name>
<servlet-class>
org.apache.catalina.ssi.SSIServlet
</servlet-class>
<init-param>
<param-name>buffered</param-name>
<param-value>1</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>expires</param-name>
<param-value>666</param-value>
</init-param>
<init-param>
<param-name>isVirtualWebappRelative</param-name>
<param-value>0</param-value>
</init-param>
<load-on-startup>4</load-on-startup>
</servlet>

2、去掉servlet映射的注释

/*<servlet-mapping>
<servlet-name>ssi</servlet-name>
<url-pattern>*.shtml</url-pattern>
</servlet-mapping>
*/

改成

<servlet-mapping>
<servlet-name>ssi</servlet-name>
<url-pattern>*.shtml</url-pattern>
</servlet-mapping>

3、在server\lib目录中找到servlets-ssi.renametojar文件,改成 servlets-ssi.jar

4、重启tomcat

 

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